document.write( "Question 139533: Graph the line with slope 1/2 passing through the point (-3,3) . \n" ); document.write( "
Algebra.Com's Answer #101717 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If you want to find the equation of line with a given a slope of \"1%2F2\" which goes through the point (\"-3\",\"3\"), you can simply use the point-slope formula to find the equation:\r
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\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=%281%2F2%29%28x--3%29\" Plug in \"m=1%2F2\", \"x%5B1%5D=-3\", and \"y%5B1%5D=3\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=%281%2F2%29%28x%2B3%29\" Rewrite \"x--3\" as \"x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=%281%2F2%29x%2B%281%2F2%29%283%29\" Distribute \"1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=%281%2F2%29x%2B3%2F2\" Multiply \"1%2F2\" and \"3\" to get \"3%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F2%29x%2B3%2F2%2B3\" Add 3 to both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F2%29x%2B9%2F2\" Combine like terms \"3%2F2\" and \"3\" to get \"9%2F2\" (note: if you need help with combining fractions, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"1%2F2\" which goes through the point (\"-3\",\"3\") is:\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F2%29x%2B9%2F2\" which is now in \"y=mx%2Bb\" form where the slope is \"m=1%2F2\" and the y-intercept is \"b=9%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=%281%2F2%29x%2B9%2F2\" and plot the point (\"-3\",\"3\"), we get (note: if you need help with graphing, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%281%2F2%29x%2B9%2F2\" through the point (\"-3\",\"3\")\r
\n" ); document.write( "\n" ); document.write( "and we can see that the point lies on the line. Since we know the equation has a slope of \"1%2F2\" and goes through the point (\"-3\",\"3\"), this verifies our answer.
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