document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21168>Question 21168</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i completly factor 8x^2-6x? thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10171 by </B><A HREF=/tutors/aboutme.mpl?userid=Here2Help><B>Here2Help(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Here2Help><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here you go:<BR>\n" );
document.write( "Original problem:<BR>\n" );
document.write( "8x2 + -6x\r<BR>\n" );
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document.write( "Reorder the terms:<BR>\n" );
document.write( "-6x + 8x2\r<BR>\n" );
document.write( "\n" );
document.write( "Factor out the Greatest Common Factor (GCF), '2x'.<BR>\n" );
document.write( "2x(-3 + 4x)<BR>\n" );
document.write( "Final result:2x(-3 + 4x)<BR>\n" );
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