document.write( "Question 139516: 3/x+3/y divided by 3/x-3/y \n" ); document.write( "
Algebra.Com's Answer #101703 by stanbon(75887)\"\" \"About 
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3/x+3/y divided by 3/x-3/y\r
\n" ); document.write( "\n" ); document.write( "(3x+3y)/xy / (3y-3x)/xy\r
\n" ); document.write( "\n" ); document.write( "Concel the xy denominators:\r
\n" ); document.write( "\n" ); document.write( "= [3(x+y)]/[3(y-x)]\r
\n" ); document.write( "\n" ); document.write( "Cancel the 3 factor in numerator and denominator.\r
\n" ); document.write( "\n" ); document.write( "= (x+y)/(y-x)\r
\n" ); document.write( "\n" ); document.write( "=================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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