document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=139476>Question 139476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you help me from here;<BR>\n" );
document.write( "The value of a two digit number is twice as large as the sum of its digits. If the digits were reversed, the resulting number would be 9 less than 5 times the original number. Find the original number.<BR>\n" );
document.write( "t = tens digit<BR>\n" );
document.write( "u = units digit<BR>\n" );
document.write( "10t+u = original number<BR>\n" );
document.write( "10u+t = the number named when the digits were reversed<BR>\n" );
document.write( "10u+t = 9-5(10t+u) <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101683 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101683\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The value of a two digit number is twice as large as the sum of its digits. If the digits were reversed, the resulting number would be 9 less than 5 times the original number. Find the original number.<BR>\n" );
document.write( "t = tens digit<BR>\n" );
document.write( "u = units digit<BR>\n" );
document.write( "10t+u = original number<BR>\n" );
document.write( "10u+t = the number named when the digits were reversed<BR>\n" );
document.write( "10u+t = 9-5(10t+u) <BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "10t + u = 2(t + u)<BR>\n" );
document.write( "10u + t = 5(10t+u)-9<BR>\n" );
document.write( "-------------------------<BR>\n" );
document.write( "Rearrange the equations:<BR>\n" );
document.write( "8t -u = 0<BR>\n" );
document.write( "49t - 5u = 9<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "solve by substitution:<BR>\n" );
document.write( "49t - 5(8t) = 9<BR>\n" );
document.write( "9t = 9<BR>\n" );
document.write( "t = 1<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "Substitute to solve for \"u\":<BR>\n" );
document.write( "u = 8t so u = 8<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "Original Number 18<BR>\n" );
document.write( "=======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );