document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=139456>Question 139456</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the solution of the exponential equation:\r<BR>\n" );
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document.write( "2^(2x+5) = 3^(x&#8722;48)\r<BR>\n" );
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document.write( "in terms of logarithms.\r<BR>\n" );
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document.write( "THANKS TO ANYONE WHO COULD HELP!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101677 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> taking log __ (2x+5)log(2)=(x-48)log(3)\r<BR>\n" );
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document.write( "distributing __ 2xlog(2)+5log(2)=xlog(3)-48log(3)\r<BR>\n" );
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document.write( "subtracting xlog(3)+5log(2) __ 2xlog(2)-xlog(3)=-48log(3)-5log(2)\r<BR>\n" );
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document.write( "factoring __ x[2log(2)-log(3)]=-48log(3)-5log(2)\r<BR>\n" );
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document.write( "dividing by 2log(2)-log(3) __ x=[-48log(3)-5log(2)]/[2log(2)-log(3)] </SPAN>\n" );
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