document.write( "Question 139391:
\n" ); document.write( "The length of a rectangle is 1 ft. more than twice the width. The area is 55 sq. ft. Find the length and width?
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Algebra.Com's Answer #101675 by checkley77(12844)\"\" \"About 
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L=2W+1
\n" ); document.write( "W(2W+1)=55
\n" ); document.write( "2W^2+W-55=0
\n" ); document.write( "(2W+11)(W-5)=0
\n" ); document.write( "W-5=0
\n" ); document.write( "W=5 IS THE WIDTH MEASUREMENT.
\n" ); document.write( "L=2*5+1
\n" ); document.write( "L=10=1
\n" ); document.write( "L=11 IS THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "5*11=55
\n" ); document.write( "55=55
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