document.write( "Question 139391:
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document.write( "The length of a rectangle is 1 ft. more than twice the width. The area is 55 sq. ft. Find the length and width? \n" );
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Algebra.Com's Answer #101675 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=2W+1 \n" ); document.write( "W(2W+1)=55 \n" ); document.write( "2W^2+W-55=0 \n" ); document.write( "(2W+11)(W-5)=0 \n" ); document.write( "W-5=0 \n" ); document.write( "W=5 IS THE WIDTH MEASUREMENT. \n" ); document.write( "L=2*5+1 \n" ); document.write( "L=10=1 \n" ); document.write( "L=11 IS THE LENGTH. \n" ); document.write( "PROOF \n" ); document.write( "5*11=55 \n" ); document.write( "55=55 \n" ); document.write( " \n" ); document.write( " |