document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=139395>Question 139395</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/061849281x/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> a chemist needs 10 liters of a 25 % acid solution. the solution is to be mixed from three solutions whose acid concentrations are 10% 20%  50% how many liters of each solution should the chemist use to satisfy the following\r<BR>\n" );
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document.write( "a   use as little as possible the 50% solution<BR>\n" );
document.write( "b   use as much as possible of the 50% solution<BR>\n" );
document.write( "c  use 2 liters of the 50% solution                this is a three part question  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101673 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101673\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a chemist needs 10 liters of a 25 % acid solution. the solution is to be mixed from three solutions whose acid concentrations are 10% 20% 50% how many liters of each solution should the chemist use to satisfy the following<BR>\n" );
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document.write( "a use as little as possible the 50% solution<BR>\n" );
document.write( "Mix it with 20% solution only<BR>\n" );
document.write( "Let x = amt of 50% solution<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(10-x) = 20% solution<BR>\n" );
document.write( "equation:<BR>\n" );
document.write( ".50(x) + .20(10-x) = .25(10)<BR>\n" );
document.write( ".5x + 2 - .2x = 2.5<BR>\n" );
document.write( ".3x = 2.5-2<BR>\n" );
document.write( "x =<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.5%2F.3 ALIGN=MIDDLE  ALT=\".5%2F.3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 1.67 liters of 50% solution required<BR>\n" );
document.write( "10 - 1.67 = 8.33 liters of 20% solution<BR>\n" );
document.write( ":<BR>\n" );
document.write( ";<BR>\n" );
document.write( "b use as much as possible of the 50% solution<BR>\n" );
document.write( "Mix it with the 10% solution only<BR>\n" );
document.write( "Let x = amt of 50% solution<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(10-x) = 10% solution<BR>\n" );
document.write( "equation:<BR>\n" );
document.write( ".50x + .10(10-x) = .25(10)<BR>\n" );
document.write( ".5x + 1 - .1x = 2.5<BR>\n" );
document.write( ".4x = 2.5 - 1<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.5%2F.4 ALIGN=MIDDLE  ALT=\"1.5%2F.4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 3.75 liters of 50% solution<BR>\n" );
document.write( "10 - 3.75 = 6.25 liters of 10% solution<BR>\n" );
document.write( ";<BR>\n" );
document.write( ":<BR>\n" );
document.write( "c use 2 liters of the 50% solution<BR>\n" );
document.write( "Mix it with 10% and the 20%; they will have to equal 8 liters<BR>\n" );
document.write( "Let x = 20% solution<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(8-x) = 10% solution<BR>\n" );
document.write( "equation:<BR>\n" );
document.write( ".20x + .10(8-x) + .50(2) = .25(10)<BR>\n" );
document.write( ".20x + .8 - .10x + 1 = 2.5<BR>\n" );
document.write( ".2x - .1x + 1.8 = 2.5<BR>\n" );
document.write( ".1x = 2.5 - 1.8<BR>\n" );
document.write( ".1x = .7<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.7%2F.1 ALIGN=MIDDLE  ALT=\".7%2F.1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 7 liters of 20% solution<BR>\n" );
document.write( "(8-7 = 1 liter of the 10% solution<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check the last one:<BR>\n" );
document.write( ".2(7) + .1(1) + .5(2) = .25(10)<BR>\n" );
document.write( "1.4 + .1 + 1 = 2.5 </SPAN>\n" );
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