document.write( "Question 139265: The perimeter of a rectangle is 74m. The length is 1 m more than twice the width. Find the demensions.
\n" ); document.write( "What is the length?
\n" ); document.write( "What is the width?\r
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\n" ); document.write( "I would also like to thank EVERYONE who has helped me since I started having to come here for your help you have been Great and I really apprciate learning from you all.
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Algebra.Com's Answer #101626 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
2L+2W=74
\n" ); document.write( "L=2W+1
\n" ); document.write( "2(2W+1)+2W=74
\n" ); document.write( "4W+2+2W=74
\n" ); document.write( "6W=74-2
\n" ); document.write( "6W=72
\n" ); document.write( "W=72/6
\n" ); document.write( "W=12 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=2*12=1
\n" ); document.write( "L=24+1
\n" ); document.write( "W=25 ANSWER FOR THE L3HGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*12=2*25=74
\n" ); document.write( "24+50=74
\n" ); document.write( "74=74
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