document.write( "Question 139265: The perimeter of a rectangle is 74m. The length is 1 m more than twice the width. Find the demensions.
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document.write( "What is the length?
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document.write( "What is the width?\r
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document.write( "Can someone help?
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Algebra.Com's Answer #101626 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 2L+2W=74 \n" ); document.write( "L=2W+1 \n" ); document.write( "2(2W+1)+2W=74 \n" ); document.write( "4W+2+2W=74 \n" ); document.write( "6W=74-2 \n" ); document.write( "6W=72 \n" ); document.write( "W=72/6 \n" ); document.write( "W=12 ANSWER FOR THE WIDTH. \n" ); document.write( "L=2*12=1 \n" ); document.write( "L=24+1 \n" ); document.write( "W=25 ANSWER FOR THE L3HGTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*12=2*25=74 \n" ); document.write( "24+50=74 \n" ); document.write( "74=74 \n" ); document.write( " \n" ); document.write( " |