document.write( "Question 139337: Help me translate this into a quadratic equation and solve. Thanks!\r
\n" ); document.write( "\n" ); document.write( "Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
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Algebra.Com's Answer #101614 by checkley77(12844)\"\" \"About 
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LET X, X+2, & X+4 BE THE 3 CONSECUTIVE EVEN INTEGERS.
\n" ); document.write( "(X+4)^2=(X+2)^2+76
\n" ); document.write( "X^2+8X+16=X^2+4X+4+76
\n" ); document.write( "8X-4X=4+76-16=0
\n" ); document.write( "4X=64
\n" ); document.write( "X=64/4
\n" ); document.write( "X=16 ANSWER.
\n" ); document.write( "16+2=18 FOR THE MIDDLE NUMBER.
\n" ); document.write( "16+4=20 FOR THE THIRD NUMBER.
\n" ); document.write( "PROOF:
\n" ); document.write( "20^2=18^2+76
\n" ); document.write( "400=324+76
\n" ); document.write( "400=400
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