document.write( "Question 139337: Help me translate this into a quadratic equation and solve. Thanks!\r
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document.write( "Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers. \n" );
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Algebra.Com's Answer #101614 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! LET X, X+2, & X+4 BE THE 3 CONSECUTIVE EVEN INTEGERS. \n" ); document.write( "(X+4)^2=(X+2)^2+76 \n" ); document.write( "X^2+8X+16=X^2+4X+4+76 \n" ); document.write( "8X-4X=4+76-16=0 \n" ); document.write( "4X=64 \n" ); document.write( "X=64/4 \n" ); document.write( "X=16 ANSWER. \n" ); document.write( "16+2=18 FOR THE MIDDLE NUMBER. \n" ); document.write( "16+4=20 FOR THE THIRD NUMBER. \n" ); document.write( "PROOF: \n" ); document.write( "20^2=18^2+76 \n" ); document.write( "400=324+76 \n" ); document.write( "400=400 \n" ); document.write( " |