document.write( "Question 139345: Some students planned for a get-together. The budget for food was $500. Five of the students failed to come because of the distance, therfore the cost of food for each member increased by $5. How many students attended the get-together? \n" ); document.write( "
Algebra.Com's Answer #101608 by checkley77(12844) ![]() You can put this solution on YOUR website! 500/X=500/(X-5)-5 \n" ); document.write( "500/X=(500-5[X-5])/(X-5) \n" ); document.write( "500/X=(500-5X+25]/(X-5) \n" ); document.write( "X(500-5X+25)=500(X-5) \n" ); document.write( "500X-5X^2+25X=500X-2500 \n" ); document.write( "-5X^2+25X+2500=0 \n" ); document.write( "-5(X^2-5X-500)=0 \n" ); document.write( "5(X-25)(X+20)=0 \n" ); document.write( "X-25=0 \n" ); document.write( "X=25 ANSWER. \n" ); document.write( "PROOF: \n" ); document.write( "500/25=500/(25-5)-5 \n" ); document.write( "20=500/20-5 \n" ); document.write( "20=25-5 \n" ); document.write( "20=20 \n" ); document.write( " |