document.write( "Question 139356: if i have a parabola with a vertex of (4,10) and x-intercepts of 0 and 8, how do i establish the quadratic equation. i came up with y=(x-4)squared + 10.\r
\n" ); document.write( "\n" ); document.write( "Ho do you establish the \"a\" of ax squared + bx + c
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Algebra.Com's Answer #101592 by stanbon(75887)\"\" \"About 
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if i have a parabola with a vertex of (4,10) and x-intercepts of 0 and 8, how do i establish the quadratic equation. i came up with y=(x-4)squared + 10.
\n" ); document.write( "Ho do you establish the \"a\" of ax squared + bx + c
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\n" ); document.write( "y = a(x-h)^2 + k
\n" ); document.write( "Vertex = (h,k) = (4,10)
\n" ); document.write( "so h=4 and k=10\r
\n" ); document.write( "\n" ); document.write( "Substitute to get:
\n" ); document.write( "y = a(x-4)^2 + 10
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\n" ); document.write( "Now use either the point (0,0) or the point (8,0) to find \"a\":
\n" ); document.write( "Using 0,0 you get 0 = a*16 + 10
\n" ); document.write( "a = -10/16 = -5/8
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\n" ); document.write( "EQUATION:
\n" ); document.write( "y = (-5/8)(x-4)^2 + 10
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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