document.write( "Question 139126:  In 1992, the FAA conducted 86,991 pre-employment drug tests on job applicants who were to be
\n" );
document.write( "engaged in safety and security-related jobs, and found that 1,143 were positive. (a) Construct a
\n" );
document.write( "95 percent confidence interval for the population proportion of positive drug tests. (b) Why is the
\n" );
document.write( "normality assumption not a problem, despite the very small value of p? \n" );
document.write( "
| Algebra.Com's Answer #101582 by stanbon(75887)      You can put this solution on YOUR website! a) I ran a 1-PropZInt test on a TI calculator to get the following interval \n" ); document.write( "0.01238 < p < 0.0139 \n" ); document.write( "------------------------- \n" ); document.write( "b) While p is small, the population is very large so np and nq \n" ); document.write( "> 5 is a reasonable assumption. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |