document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=139292>Question 139292</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimter of a triangle is 46 cm. The triangle is isosceles now, but if its base were lenghtened by 6cm and each leg were shortened by 2 cm, it would be equilaterial.  Find the base of the original triangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101579 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101579\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let an isosceles side be s and the base be b.<BR>\n" );
document.write( "A) 2s+b=46<BR>\n" );
document.write( "B) s-2=b+6 <BR>\n" );
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document.write( "B) s=b+8<BR>\n" );
document.write( "A) <BR>\n" );
document.write( "2(b+8)+b=46 Substitute b+8 for s.<BR>\n" );
document.write( "2b+16+b=46<BR>\n" );
document.write( "3b+16=46<BR>\n" );
document.write( "3b=30<BR>\n" );
document.write( "b=10 Ans.<BR>\n" );
document.write( "s=18<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "Sides of original triangle: 18, 18, 10<BR>\n" );
document.write( "Sides of equilateral triangle: 16, 16, 16<BR>\n" );
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document.write( "Ed<BR>\n" );
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