document.write( "Question 139124: Please solve this:
\n" ); document.write( "A retangular piece of wood is 12cm longer than it is wide. A strip 1cm wide is cut off all around. This decreses the area by 120 square cm. What were the original dimensions?
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Algebra.Com's Answer #101555 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangular piece of wood is 12 cm longer than it is wide. A strip 1 cm wide is cut off all around. This decreases the area by 120 square cm. What were the original dimensions?
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\n" ); document.write( "Let x = width of the wood
\n" ); document.write( "then
\n" ); document.write( "(x+12) = length
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\n" ); document.write( "Original area = x(x+12) = (x^2 + 12x)
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\n" ); document.write( "Dimensions after the 1 cm strip removed
\n" ); document.write( "Width = (x-2)
\n" ); document.write( "Length = (x+12) - 2 = (x+10)
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\n" ); document.write( "Area now: (x-2)(x+10) = (x^2 + 8x - 20)
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\n" ); document.write( "The equation:
\n" ); document.write( " old area - new area = 120
\n" ); document.write( "(x^2 + 12x) - (x^2 + 8x - 20) = 120
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\n" ); document.write( "x^2 + 12x - x^2 - 8x + 20 = 120
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\n" ); document.write( "12x - 8x = 120 - 20
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\n" ); document.write( "4x = 100
\n" ); document.write( "x = \"100%2F4\"
\n" ); document.write( "x = 25 cm is the original width
\n" ); document.write( "then
\n" ); document.write( "(25 + 12) = 37 cm is the original length
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\n" ); document.write( "Check solution by find the areas:
\n" ); document.write( "37*25 = 925
\n" ); document.write( "35*23 = 805
\n" ); document.write( "-----------
\n" ); document.write( "diff: = 120
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