document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21134>Question 21134</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how would you solve an equation with variables on both sides for example <BR>\n" );
document.write( "12-2a=-5a-9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10154 by </B><A HREF=/tutors/aboutme.mpl?userid=wuwei96815><B>wuwei96815(245)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wuwei96815><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10154\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You cannot solve this equation until you get all the variables on the same side.\r<BR>\n" );
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document.write( "12-2a = -5a-9  First, add 2a to each side of the equation.\r<BR>\n" );
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document.write( "You get:  12-2a+2a = -5a-9+2a<BR>\n" );
document.write( "Simplified it becomes:  12 = -3a-9  Now, add 9 to each side.<BR>\n" );
document.write( "You get:  12+9 = -3a-9+9<BR>\n" );
document.write( "Simplified it becomes:  21 = -3a<BR>\n" );
document.write( "21/-3 = a\r<BR>\n" );
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document.write( "-7 = a\r<BR>\n" );
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document.write( "You can check the correctness of this answer by substituting -7 for a in the original equation. </SPAN>\n" );
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