document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=139178>Question 139178</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me i really need ur help as soon as possible.\r<BR>\n" );
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document.write( "Find three consecutive numbers such that 3 times the middle one shall be greater than the sum of the other two by 15. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101501 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101501\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive numbers such that 3 times the middle one shall be greater than the sum of the other two by 15.<BR>\n" );
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document.write( "Three consecutive numbers: x, (x+1), (x+2)<BR>\n" );
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document.write( "\" 3 times the middle one shall be greater than the sum of the other two by 15.\"<BR>\n" );
document.write( "3(s+1) = x + (x+2) + 15<BR>\n" );
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document.write( "3x + 3 = 2x + 17<BR>\n" );
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document.write( "3x - 2x = 17 - 3<BR>\n" );
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document.write( "x = 14, 15, 16 are the three numbers:<BR>\n" );
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document.write( "Check in the statement:<BR>\n" );
document.write( "3 times the middle one shall be greater than the sum of the other two by 15.<BR>\n" );
document.write( "3(15) = 14 + 16 + 15 </SPAN>\n" );
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