document.write( "Question 20001: A student walks and jogs to college each day. The student averages 5 km/h walking and 9 km/h jogging. The distance from home to college is 8 km, and the student makes the trip in 1 hour. How far does the student jog? \n" ); document.write( "
Algebra.Com's Answer #10146 by suresh(20)\"\" \"About 
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Let x be the distance travelled by walk.
\n" ); document.write( "Let y be the distance travelled by jog.
\n" ); document.write( "Given x + y = 8-----> (1) ( Since total distance is 8 km)
\n" ); document.write( "We know, time = distance / speed.
\n" ); document.write( "The average speed of the student by walk = 5 km/hr.
\n" ); document.write( "The average speed of the student by jog = 9 km/hr.
\n" ); document.write( "The time taken by walk = x/5 hr.
\n" ); document.write( "The time taken by jog = y/9 hr.
\n" ); document.write( "Total time taken by the student = 1 hr.
\n" ); document.write( "So, x/5 + y/9 = 1
\n" ); document.write( "9x + 5y =45 -----> (2)
\n" ); document.write( "Multiply (1) by 5, we get, 5x+5y=40 ----->(3)
\n" ); document.write( "Subtract (3) from (2), 4x = 5
\n" ); document.write( "x=5/4=1.25
\n" ); document.write( "Plug the value in (1), y = 8 - 1.25 = 6.75.
\n" ); document.write( "Hence the student jogs 6.75km.\r
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