document.write( "Question 139107: Could you please help me out?
\n" ); document.write( "The perimeter of a room is 96 feet. The room is rectangular in shape and the length of the room is 8 feet more than the width. What is the area of the room?
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Algebra.Com's Answer #101458 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
2X+2(X+4)=96
\n" ); document.write( "2X+2X+8=96
\n" ); document.write( "4X=96-8
\n" ); document.write( "4X=88
\n" ); document.write( "X=88/4
\n" ); document.write( "X=22 THE WIDTH OF THE ROOM.
\n" ); document.write( "22=4=26 FOR THE LENGTH OF THE ROOM.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*22=2*26=96
\n" ); document.write( "44+52=96
\n" ); document.write( "96=96
\n" ); document.write( "AREA=22*26=572 FEET^2 IS THE AREA OF THE ROOM. \r
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