document.write( "Question 139080: One brine solution contains 6% salt and another brine solution contains 2% salt. How many pints of each solution should be mixed to produce 48 pints of brine solution that is 5% salt? \n" ); document.write( "
Algebra.Com's Answer #101454 by ankor@dixie-net.com(22740)\"\" \"About 
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One brine solution contains 6% salt and another brine solution contains 2% salt. How many pints of each solution should be mixed to produce 48 pints of brine solution that is 5% salt?
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\n" ); document.write( "Let x = amt of 6% salt solution
\n" ); document.write( "It says the final amt will be 48 pints, therefore
\n" ); document.write( "(48-x) = amt of 2% solution
\n" ); document.write( ":
\n" ); document.write( ".06x + .02(48-x) = .05(48)
\n" ); document.write( ".06x + .96 - .02x = 2.4
\n" ); document.write( ".06x - .02x = 2.4 - .96
\n" ); document.write( ".04x = 1.44
\n" ); document.write( "x = \"1.44%2F.04\"
\n" ); document.write( "x = 36 pints of 6% solution
\n" ); document.write( "and
\n" ); document.write( "48 - 36 = 12 pints of 2% solution
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check our answers in the original equation
\n" ); document.write( ".06(36) + .02(12) = .05(48)
\n" ); document.write( " 2.16 + .24 = 2.4 \n" ); document.write( "
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