document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=139002>Question 139002</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 218 ft. One side is twice the second side. The third side is 42 more 17than the second side. Find the length of each side.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101425 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET 2X BE THE FIRST SIDE<BR>\n" );
document.write( "X FOR THE SECOND SIDE<BR>\n" );
document.write( "X+42 FOR THE THIRD SIDE<BR>\n" );
document.write( "2X+X+X+42=218<BR>\n" );
document.write( "4X=218-42<BR>\n" );
document.write( "4X=176<BR>\n" );
document.write( "X=176/4<BR>\n" );
document.write( "X=44 ANSWER FOR THE SECOND SIDE<BR>\n" );
document.write( "2*44=88 FOR THE FIRST SIDE<BR>\n" );
document.write( "44+42=86 FOR THE THIRD SIDE<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "44+88+86=218<BR>\n" );
document.write( "218=218<BR>\n" );
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