document.write( "Question 139000: every 15 min. the fast train arrives & waits 4 min. Then 4 min. after the fast train leaves, the local train arrives & waits 3 min. If you arrive at the station at a random time during the rush period, find the probability that the fast train will be waiting and find the probability that no train will be there.\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #101416 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! The fast train arrives every 15 minutes and waits 4 minutes. That means that the fast train is there 4 out of every 15 minutes. Pick a random minute out of any 15, and you have 4 possibilities out of 15 that the fast train will be there; probability \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the second part of the problem. The fast train is at the station for a total of 4 minutes out of 15, and the local is there 3 minutes out of 15. Since there is no overlap, the total time that any train is there is 7 minutes. That means out of every 15 minutes, there are 8 minutes when there is no train there at all. Hence, the probability of having to wait to get on a train is |