document.write( "Question 21050: This is from my 8th grade honors algebra... \r
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document.write( "Tori invested $24,000 , part at 8% and the rest at 7.2%. How much did she invest at each rate if her income from the 8% investment is two-thirds of that of the 7.2% investment?\r
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document.write( " I've made a chart...\r
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document.write( " Amount invested x rate = interest income\r
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document.write( " X x 0.08 = 0.08X = y
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document.write( " ($24,000-X) x 0.072 = 0.072($24,000-X) = 2/3y\r
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document.write( "Then I'm totally stuck, we haven't solved with 2 unknowns yet! \n" );
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Algebra.Com's Answer #10137 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Try this: \n" ); document.write( "Let x = the amount invested at 8% (0.08). \n" ); document.write( "The interest on this amount is written as: 0.08x \n" ); document.write( "Let (24000 - x) = the amount invested at 7.2% (0.072). \n" ); document.write( "The interest on this amount is written as: 0.072(24000 - x)\r \n" ); document.write( "\n" ); document.write( "The interest on the 8% part is 2/3 the interest on the 7.2% part. \n" ); document.write( "So, you can say: \n" ); document.write( "\n" ); document.write( "Now you can write the equation to solve this problem:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, $9,000.00 was invested at 8% and ($24,000.00 - $9,000.00 = $15,000.00) was invested at 7.2%\r \n" ); document.write( "\n" ); document.write( "Check:\r \n" ); document.write( "\n" ); document.write( "0.08($9,000.00) = $720.00 The interest on the amount invested at 8% \n" ); document.write( "0.072($15,000.00) = $1,080.00 The interest on the amount invested at 7.2%.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |