document.write( "Question 138885: Solve.
\n" ); document.write( "0.5x + 6 <_ 1.3x - 3\r
\n" ); document.write( "\n" ); document.write( "HELP PLEASE!! WIll someone help. \n" ); document.write( "
Algebra.Com's Answer #101368 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
0.5x + 6 <= 1.3x - 3
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\n" ); document.write( "Get rid of those annoying decimals: multiply equation by 10 and you have:
\n" ); document.write( "5x + 60 <= 13x - 30
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\n" ); document.write( "Subtract 13x and 60 from both sides:
\n" ); document.write( "5x - 13x <= -30 - 60
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\n" ); document.write( "-8x <= -90
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\n" ); document.write( "We need the variable to be positive, multiply both sides by -1;
\n" ); document.write( "We have to reverse the inequality sign, when we do this:
\n" ); document.write( "8x >= 90
\n" ); document.write( "x >= \"90%2F8\"
\n" ); document.write( "x >= 11.25
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\n" ); document.write( "Check solution in original equation when x = 11.25
\n" ); document.write( "0.5(11.25) + 6 = 1.3(11.25) - 3
\n" ); document.write( "5.625 + 6 = 14.625 - 3; equality
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\n" ); document.write( "Check solution when x > 11.25, let's use 12
\n" ); document.write( "0.5(12) + 6 < 1.3(12) - 3
\n" ); document.write( "6 + 6 < 15.6 - 3
\n" ); document.write( "12 < 12.6 is true
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\n" ); document.write( "Did this make sense to you? Any questions? \n" ); document.write( "
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