document.write( "Question 138886: -2x < x + 1 < 7 \r
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Algebra.Com's Answer #101347 by edjones(8007)![]() ![]() You can put this solution on YOUR website! -2x < x + 1 < 7 \n" ); document.write( ". \n" ); document.write( "-2x \n" ); document.write( "-3x<1 \n" ); document.write( "x>-1/3 reverse the inequality sign when mult. or div. by a negative number. \n" ); document.write( ". \n" ); document.write( "x+1<7 \n" ); document.write( "x<6 \n" ); document.write( ". \n" ); document.write( "-1/3 < x < 6 \n" ); document.write( ". \n" ); document.write( "Ed |