document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=138888>Question 138888</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem is:  A roller coaster carries 92 people altogether.  Some of its cars carry 4 passengers, and the rest carry 6 passengers.  There are three fewer 6-passenger cars than 4-passenger cars.  How many 4-passenger cars are there? <BR>\n" );
document.write( "I started a problem with f=4passenger cars & f-3=6passenger cars, but this doesn't work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101345 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let f=number of 4 passenger cars, f-3=number of 6 passenger cars.<BR>\n" );
document.write( "4f+6(f-3)=92<BR>\n" );
document.write( "4f+6f-18=92<BR>\n" );
document.write( "10f-18+18=92+18<BR>\n" );
document.write( "10f=110<BR>\n" );
document.write( "f=11 Ans.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "11*4=44<BR>\n" );
document.write( "8*6=48<BR>\n" );
document.write( "44+48=92<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );