document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=138922>Question 138922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a dance floor is 34m and the area is 60m squared.  What are the lengths of the sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101341 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101341\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2w=34<BR>\n" );
document.write( "Lw=60<BR>\n" );
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document.write( "L=60/w<BR>\n" );
document.write( "2(60/w)+2w=34 <BR>\n" );
document.write( "120/w+2w=34<BR>\n" );
document.write( "120+2w^2=34w multiply each side by w to eliminate fraction.<BR>\n" );
document.write( "2w^2-34w+120=0<BR>\n" );
document.write( "2(w^2-17w+60)=0<BR>\n" );
document.write( "(w-12)(w-5)=0<BR>\n" );
document.write( "w=12, w=5<BR>\n" );
document.write( "Dimensions of the dance floor L=12 m, w=5 m or vice versa.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );