document.write( "Question 21009: Hi,
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document.write( "I do not see any dection for the problem I am asking for a solution for. According to my book this is: Complete the ordered pairs so that each is a solution for the given equation. 3x + 4y = 12 (0, ),( ,3/4),( ,0),(8/3, ).
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document.write( "I am not sure if I wrote the fractions correctly 3/4 and 8/3.
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document.write( "Thank you for your help
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Algebra.Com's Answer #10133 by algebrapro18(249)![]() ![]() ![]() You can put this solution on YOUR website! well all you have to do is plug in the number for the correct varialbe and solve.\r \n" ); document.write( "\n" ); document.write( "pluging 0 in for x \n" ); document.write( "3(0)+4y=12 \n" ); document.write( "simplifying \n" ); document.write( "4y=12 \n" ); document.write( "dividing both sides by 4 \n" ); document.write( "y=3 \n" ); document.write( "(0,3) \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "plinging 3/4 in for y \n" ); document.write( "3x+4(3/4)=12 \n" ); document.write( "simplifying \n" ); document.write( "3x+3=12 \n" ); document.write( "subtracting 3 from both sides \n" ); document.write( "3x=9 \n" ); document.write( "dividing both sides by 3 \n" ); document.write( "x=3 \n" ); document.write( "(3,3/4) \r \n" ); document.write( "\n" ); document.write( "Pluging in 0 for y you get \n" ); document.write( "3x+4(0)=12 \n" ); document.write( "simplifying \n" ); document.write( "3x=12 \n" ); document.write( "dividing both sides by 3 \n" ); document.write( "x=4 \n" ); document.write( "(4,0) \r \n" ); document.write( "\n" ); document.write( "pluging in 8/3 for x you get \n" ); document.write( "3(8/3)+4y=12 \n" ); document.write( "simplifying \n" ); document.write( "8+4y=12 \n" ); document.write( "subtracting 8 from both sides \n" ); document.write( "4y=4 \n" ); document.write( "dividing both sides by 4 \n" ); document.write( "y=1 \n" ); document.write( "(8/3,1) \n" ); document.write( " |