document.write( "Question 21009: Hi,
\n" ); document.write( "I do not see any dection for the problem I am asking for a solution for. According to my book this is: Complete the ordered pairs so that each is a solution for the given equation. 3x + 4y = 12 (0, ),( ,3/4),( ,0),(8/3, ).
\n" ); document.write( "I am not sure if I wrote the fractions correctly 3/4 and 8/3.
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\n" ); document.write( "\n" ); document.write( "Thank you for your help
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Algebra.Com's Answer #10133 by algebrapro18(249)\"\" \"About 
You can put this solution on YOUR website!
well all you have to do is plug in the number for the correct varialbe and solve.\r
\n" ); document.write( "\n" ); document.write( "pluging 0 in for x
\n" ); document.write( "3(0)+4y=12

\n" ); document.write( "simplifying
\n" ); document.write( "4y=12

\n" ); document.write( "dividing both sides by 4
\n" ); document.write( "y=3

\n" ); document.write( "(0,3)

\r
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\n" ); document.write( "\n" ); document.write( "plinging 3/4 in for y
\n" ); document.write( "3x+4(3/4)=12

\n" ); document.write( "simplifying
\n" ); document.write( "3x+3=12

\n" ); document.write( "subtracting 3 from both sides
\n" ); document.write( "3x=9

\n" ); document.write( "dividing both sides by 3
\n" ); document.write( "x=3

\n" ); document.write( "(3,3/4)

\r
\n" ); document.write( "\n" ); document.write( "Pluging in 0 for y you get
\n" ); document.write( "3x+4(0)=12

\n" ); document.write( "simplifying
\n" ); document.write( "3x=12

\n" ); document.write( "dividing both sides by 3
\n" ); document.write( "x=4

\n" ); document.write( "(4,0)

\r
\n" ); document.write( "\n" ); document.write( "pluging in 8/3 for x you get
\n" ); document.write( "3(8/3)+4y=12

\n" ); document.write( "simplifying
\n" ); document.write( "8+4y=12

\n" ); document.write( "subtracting 8 from both sides
\n" ); document.write( "4y=4

\n" ); document.write( "dividing both sides by 4
\n" ); document.write( "y=1

\n" ); document.write( "(8/3,1)
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