document.write( "Question 138869: Solve foe x:
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document.write( "a) (0.5)^(x+2)=3^x
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document.write( "b) 1/8(16^(2x-1))=(sqrt2)^x
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document.write( "c)2-log(5x)=log(x+1) \n" );
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Algebra.Com's Answer #101328 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a) (0.5)^(x+2)=3^x \n" ); document.write( "(x+2)log(0.5) = xlog3 \n" ); document.write( "xlog(0.5) + 2log(0.5) = xlog3 \n" ); document.write( "x(log0.5-log3) = -2log(0.5) \n" ); document.write( "x log((1/2)/3) = log(1/2)^(-2) \n" ); document.write( "x log(1/6) = log 4 \n" ); document.write( "x = log4 / log(1/6) \n" ); document.write( "x = -0.773706... \n" ); document.write( "---------------------------- \r \n" ); document.write( "\n" ); document.write( "b) 1/8(16^(2x-1))=(sqrt2)^x \n" ); document.write( "16^(2x-1) = 8*(sqrt2)^x \n" ); document.write( "2^[4(2x-1)] = 2^3*2^(x/2) \n" ); document.write( "2^(8x-4] = 2^[(x+6)/2] \n" ); document.write( "8x-4 = (x+6)/2 \n" ); document.write( "16x-8 = x+6 \n" ); document.write( "15x = 14 \n" ); document.write( "x = 14/15 \n" ); document.write( "---------------------------\r \n" ); document.write( "\n" ); document.write( "c)2-log(5x)=log(x+1) \n" ); document.write( "2 = log(5x)+log(x+1) \n" ); document.write( "2 = log[5x^2+5x] \n" ); document.write( "5x^2+5x=10^2 \n" ); document.write( "5x^2+5x-100 = 0 \n" ); document.write( "x^2+x-20 = 0 \n" ); document.write( "(x+5)(x-4) = 0 \n" ); document.write( "Positive solution: \n" ); document.write( "x = 4 \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |