document.write( "Question 138883This question is from textbook
\n" ); document.write( ": 1/6(y+42)-15=-3 \n" ); document.write( "
Algebra.Com's Answer #101318 by ankor@dixie-net.com(22740)\"\" \"About 
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1/6(y+42)-15=-3
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\n" ); document.write( "Add 15 to both sides:
\n" ); document.write( "\"1%2F6\"(y+42) = 15 - 3
\n" ); document.write( "\"1%2F6\"(y+42) = 12
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\n" ); document.write( "Multiply both sides by 6:
\n" ); document.write( "y + 42 = 6(12)
\n" ); document.write( "y + 42 = 72
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\n" ); document.write( "Subtract 42 from both sides:
\n" ); document.write( "y = 72 - 42
\n" ); document.write( "y = 30
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\n" ); document.write( "Check solution in original equation:
\n" ); document.write( "\"1%2F6\"(30+42) - 15 = -3
\n" ); document.write( "\"1%2F6\"(72) - 15 = -3
\n" ); document.write( " 12 - 15 = -3; confirms our solution\r
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