document.write( "Question 138837: Debbie traveled by boat 5 miles upstream to fish in her favorite spot. Because of the 4-mph current, it took her 40 minutes longer to get there than to return. How fast will her boat go in still water? \n" ); document.write( "
Algebra.Com's Answer #101308 by ankor@dixie-net.com(22740)\"\" \"About 
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Debbie traveled by boat 5 miles upstream. Because of the 4-mph current, it took her 40 minutes longer to get there than to return. How fast will her boat go in still water?
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\n" ); document.write( "Let s = speed of boat in still water
\n" ); document.write( "then
\n" ); document.write( "(s-4) = speed upstream
\n" ); document.write( "and
\n" ); document.write( "(s+4) = speed downstream
\n" ); document.write( ":
\n" ); document.write( "Change 40 min to hrs: 40/60 = \"2%2F3\"hr
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\n" ); document.write( "Write a time equation: Time = Dist/speed:
\n" ); document.write( "Time upstream = time downstream + 2/3 hr
\n" ); document.write( "\"5%2F%28%28s-4%29%29\" = \"5%2F%28%28s%2B4%29%29\" + \"2%2F3\"
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\n" ); document.write( "Multiply equation by 3(s+4(s-4) to get rid of the denominators:
\n" ); document.write( "3(s+4)(s-4)*\"5%2F%28%28s-4%29%29\" = 3(s+4)(s-4)*\"5%2F%28%28s%2B4%29%29\" + 3(s+4)(s-4)*\"2%2F3\"
\n" ); document.write( "Cancel out the denominators:
\n" ); document.write( "3(s+4)*5 = 3(s-4)*5 + 2(s+4)(s-4)
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\n" ); document.write( "15(s+4) = 15(s-4) + 2(s^2 - 16)
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\n" ); document.write( "15s + 60 = 15s - 60 + 2s^2 - 32
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\n" ); document.write( "0 = 2s^2 + 15s - 15s - 60 - 60 - 32; combine on the right
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\n" ); document.write( "2s^2 - 152 = 0
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\n" ); document.write( "2s^2 = 152
\n" ); document.write( "s^2 =\"152%2F2\"
\n" ); document.write( "s = \"sqrt%2876%29\"
\n" ); document.write( "s = 8.7 mph speed in still water
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\n" ); document.write( "Check the times of each trip, using decimals:
\n" ); document.write( "5/4.7 = 1.064 hrs
\n" ); document.write( "5/12.7 = .394 hrs
\n" ); document.write( "------------------
\n" ); document.write( "Differs .67 hrs; confirms our solution
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