document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=138770>Question 138770</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help.\r<BR>\n" );
document.write( "\n" );
document.write( "Use the compound interest formulas A=P(1+r/n)^nt and A =P^ert to solve. Find the accumulated value of an investment of $17,000 at 12% compounded annually for 18 years. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101302 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 17,000(1+.12)^18<BR>\n" );
document.write( "17,000(1.12)^18<BR>\n" );
document.write( "17,000*7.69<BR>\n" );
document.write( "130,729 ANSWER FOR THE COMPOUNDING ANNUALLY.<BR>\n" );
document.write( "-------------------------------------------------------------<BR>\n" );
document.write( "I BELIEVE THIS CORRECT FORMULA IS [Pe^RT] WHERE e=2.718, R=ANNUAL RATE & T=NUMBER OF YEARS IS FOR A CONTINUOUS COMPOUNDING INVESTMENT.<BR>\n" );
document.write( "17,000*2.7183^(.12*18)<BR>\n" );
document.write( "17,000*2.7183^2.16<BR>\n" );
document.write( "17,000*8.67<BR>\n" );
document.write( "147,390 ANSWER. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );