document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=138811>Question 138811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you show me how to work out this word problem: A shopping center has a rectangular area of 40,000 square yards enclosed on 3 sides for a parking lot. The length is 200 yards more than twice the width. What are the dimensions of the lot? Thanks, Tyler </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101294 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101294\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W+200<BR>\n" );
document.write( "W(2W+200)=40,000<BR>\n" );
document.write( "2W^2+200W-40,000=0<BR>\n" );
document.write( "2(W^2+100W-20,000)=0<BR>\n" );
document.write( "2(W+200)(W-100)=0<BR>\n" );
document.write( "W-100=0<BR>\n" );
document.write( "W=100 ANSWER FOR THE WIDTH.<BR>\n" );
document.write( "L=2*100+200<BR>\n" );
document.write( "L=200+200<BR>\n" );
document.write( "L=400 ANSWER FOR THE LENGTH.<BR>\n" );
document.write( "100*400=40,000<BR>\n" );
document.write( "40,000=40,000<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );