document.write( "Question 138828: 1 ounce of the mixture containing 6% salt is to be mixed with 2 ounces of a mixture which is 15% salt, in order to obtain a solution which is 12% salt. What is the percentage of salt in the resulting solution?\r
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document.write( "when i try to do it on this website, it gives a syntax error on the last step so i can't see the answer spmebody please tell me the answer please. \n" );
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Algebra.Com's Answer #101292 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1 ounce of the mixture containing 6% salt is to be mixed with 2 ounces of a mixture which is 15% salt, in order to obtain a solution which is 12% salt. What is the percentage of salt in the resulting solution? \n" ); document.write( "---------------------- \n" ); document.write( "6% solution DATA; \n" ); document.write( "Amt = 1 oz ;Amt of salt = 0.06 oz \n" ); document.write( "------------------------- \n" ); document.write( "15% solution DATA; \n" ); document.write( "Amt = 2 oz ; Amt of salt = 0.15*2 = 0.30 oz \n" ); document.write( "---------------------------- \n" ); document.write( "12% mixture DATA: \n" ); document.write( "Amt = 3 oz ; Amt of salt = 0.12*3 = 0.36 oz \n" ); document.write( "----------------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "Amt of mixtue: 3 oz \n" ); document.write( "Amt of salt in the mixture: 0.36 oz \n" ); document.write( "Percent of salt in mixture = 0.36/3 = 0.12 = 12% \n" ); document.write( "================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |