document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=138827>Question 138827</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PROBLEM:<BR>\n" );
document.write( "SOLVE THE EQUATION BY COMPLETING THE SQUARE AND APPLYING THE SQUARE ROOT PROPERTY.<BR>\n" );
document.write( "4y^2-12y+13=0<BR>\n" );
document.write( "THIS PROBELM IS VERY DIFFICULT FOR ME TO UNDERSTAND I KNOW THIS MUCH SO FAR BUT I GET STUCK CAN YOU PLEASE HELP!!<BR>\n" );
document.write( "4y^2-12y=-13<BR>\n" );
document.write( "4y^2-12y+(-12/2)^2=-13+(-12-2)^2<BR>\n" );
document.write( "this is as far as i can get please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101287 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101287\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4y^2-12y+13=0\r<BR>\n" );
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document.write( "4y^2 - 12y = -13\r<BR>\n" );
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document.write( "4(y^2 - 3y + ?) = -13 + 4*?\r<BR>\n" );
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document.write( "4(y^2-3y+(3/2)^2) = -13 + 4*(3/2)^2\r<BR>\n" );
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document.write( "4(y - (3/2))^2 = -13 +9<BR>\n" );
document.write( "Divide both sides by 4 to get:\r<BR>\n" );
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document.write( "(y-(3/2))^2 = -1<BR>\n" );
document.write( "Take the square root of both sides to get:\r<BR>\n" );
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document.write( "y-(3/2) = +/- i<BR>\n" );
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document.write( "y = [(3/2) + i] or y = [(3/2) - i]\r<BR>\n" );
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document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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