document.write( "Question 138755: x-6= the square root of 3x \n" ); document.write( "

Algebra.Com's Answer #101241 by edjones(8007) $\"\"$ $\"About$

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x-6=sqrt(3x)
\n" ); document.write( "(x-6)^2=3x
\n" ); document.write( "x^2-12x+36=3x
\n" ); document.write( "x^2-15x+36=0
\n" ); document.write( "(x-12)(x-3)=0
\n" ); document.write( "x=12, x=3
\n" ); document.write( ".
\n" ); document.write( "Always check:
\n" ); document.write( "12-6=sqrt(3*12)
\n" ); document.write( "6=sqrt(36) true
\n" ); document.write( ".
\n" ); document.write( "3-6=sqrt(3*3)
\n" ); document.write( "-3=sqrt(9) false
\n" ); document.write( ".
\n" ); document.write( "x=12 is the only answer.
\n" ); document.write( ".
\n" ); document.write( "Ed \n" ); document.write( "

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