document.write( "Question 138707: a grocer mixes cookies worth 80 cents a kg with cookies worth 95 cents a kg making a mixture selling at 85 cents a kg. If he mixes 60 kilograms , how many kilograms of each kind does he use? \n" ); document.write( "
Algebra.Com's Answer #101213 by josmiceli(19441)\"\" \"About 
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Let \"a\" = the kgs of $.80/kg cookies needed
\n" ); document.write( "Let \"b\" = the kgs of $.95/kg cookies needed
\n" ); document.write( "In words, the problem is:
\n" ); document.write( "(kgs $.80/kg cookies) x ($.80/kg) + (kgs $.95/kg cookies) x ($.95/kg) /
\n" ); document.write( "(kgs $.80/kg cookies + kgs $.95/kg cookies) = $.85/kg
\n" ); document.write( "or in symbols,
\n" ); document.write( "\"%28.8a+%2B+.95b%29+%2F+%28a+%2B+b%29+=+.85\" cents/kg
\n" ); document.write( "Also given is:
\n" ); document.write( "\"a+%2B+b+=+60\" kg
\n" ); document.write( "\"%28.8a+%2B+.95b%29+%2F+60+=+.85\"
\n" ); document.write( "\".8a+%2B+.95b+=+60%2A.85\"
\n" ); document.write( "\".8a+%2B+.95%2860+-+a%29+=+51\"
\n" ); document.write( "\".8a+%2B+57+-+.95a+=+51\"
\n" ); document.write( "\"-.15a+=+-6\"
\n" ); document.write( "\"a+=+40\"
\n" ); document.write( "\"b+=+60+-+a\"
\n" ); document.write( "\"b+=+60+-+40\"
\n" ); document.write( "\"b+=+20\"
\n" ); document.write( "The grocer needs to mix 40 kg of $.80/kg cookies and 20 kg of $.95/kg
\n" ); document.write( "cookies
\n" ); document.write( "check answer:
\n" ); document.write( "\"%28.8a+%2B+.95b%29+%2F+%28a+%2B+b%29+=+.85\"
\n" ); document.write( "\"%28.8%2A40+%2B+.95%2A20%29+%2F+60+=+.85\"
\n" ); document.write( "\"%2832+%2B+19%29%2F+60+=+.85\"
\n" ); document.write( "\"51%2F60+=+.85\"
\n" ); document.write( "\".85+=+.85\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );