document.write( "Question 138701: The parabola with equation \"y-3=%28x-4%29%5E2\" has it's vertex at (4,3) and passes through (5,4). Find an equation of a different parabola with its vertex at (4,3)that passes through (5,4). Can't seem to figure this out. Do i just switch the x and y?
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Algebra.Com's Answer #101210 by Edwin McCravy(20060)\"\" \"About 
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The parabola with equation \"y-3=%28x-4%29%5E2\" has it's vertex at (4,3) and passes through (5,4). Find an equation of a different parabola with its vertex at (4,3)that passes through (5,4). Can't seem to figure this out. Do i just switch the x and y?
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document.write( "Here's the graph of \"y-3=%28x-4%29%5E2\" with the vertex (4,3) and \r\n" );
document.write( "the point (5,4).\r\n" );
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document.write( "That is a parabola which opens upward.  Let's sketch in one in\r\n" );
document.write( "green that would have that same vertex(4,3) and pass through \r\n" );
document.write( "that same point (5,4). It will have to open to the right.\r\n" );
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document.write( "A parabola which open to the right or left has equation\r\n" );
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document.write( "\"%28y-k%29%5E2=4p%28x-h%29\"\r\n" );
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document.write( "So we substitute (h,k) = (4,3) \r\n" );
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document.write( "\"%28y-3%29%5E2=4p%28x-4%29\"\r\n" );
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document.write( "Now we know that since (x,y) = (5,4) is a point on the\r\n" );
document.write( "graph, that point must satisfy the equation: \r\n" );
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document.write( "So\r\n" );
document.write( "\"%284-3%29%5E2=4p%285-4%29\"\r\n" );
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document.write( "\"1%5E2=4p%281%29\"\r\n" );
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document.write( "\"1=4p\"\r\n" );
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document.write( "\"1%2F4=p\" \r\n" );
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document.write( "Therefore the equartion is found by substituting \"p=1%2F4\"\r\n" );
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document.write( "into \"%28y-3%29%5E2=4p%28x-4%29\"\r\n" );
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document.write( "or\r\n" );
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document.write( "\"%28y-3%29%5E2=4%281%2F4%29%28x-4%29\"\r\n" );
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document.write( "\"%28y-3%29%5E2=1%28x-4%29\"\r\n" );
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document.write( "\"%28y-3%29%5E2=x-4\"\r\n" );
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document.write( "Edwin

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