document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20141>Question 20141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a vertical wall 18 feet high casts a shadow that is 6 feet wide. If Joe is 5'3' tall, how far away from the wall can he stand and still be entirely in the shade? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10120 by </B><A HREF=/tutors/aboutme.mpl?userid=kapilsinghi><B>kapilsinghi(68)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kapilsinghi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10120\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 18f cast 6f shadow<BR>\n" );
document.write( "5.25 feet will cast 5.25*6/18 = 5.25/3 = 1.75f\r<BR>\n" );
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document.write( "if second shadow is to be completely merged in the first one then the person should be standing 6 - 1.75 feet from wall<BR>\n" );
document.write( " = 4.25 feet from wall\r<BR>\n" );
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