document.write( "Question 138682: Graph \"y=%283x%29%2F%28x%5E2-5x%2B6%29%29\" \n" ); document.write( "
Algebra.Com's Answer #101194 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"y=%283x%29%2F%28x%5E2-5x%2B6%29%29\" Start with the given function\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Looking at the numerator \"3x\", we can see that the degree is \"1\" since the highest exponent of the numerator is \"1\". For the denominator \"x%5E2-5x%2B6\", we can see that the degree is \"2\" since the highest exponent of the denominator is \"2\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Horizontal Asymptote: \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since the degree of the numerator (which is \"1\") is less than the degree of the denominator (which is \"2\"), the horizontal asymptote is always \"y=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the horizontal asymptote is \"y=0\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Vertical Asymptote: \r
\n" ); document.write( "\n" ); document.write( "To find the vertical asymptote, just set the denominator equal to zero and solve for x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2-5x%2B6=0\" Set the denominator equal to zero\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Now let's use the quadratic formula to solve for x. If you need help with the quadratic formula, check out this solver.\r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( " After using the quadratic formula, we get the solutions\r
\n" ); document.write( "\n" ); document.write( " \"x=3\" or \"x=2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " So this means the vertical asymptotes are \"x=3\" or \"x=2\"
\n" ); document.write( " \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " X-Intercept(s) \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=%283x%29%2F%28x%5E2-5x%2B6%29%29\" Start with the given function\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0=%283x%29%2F%28x%5E2-5x%2B6%29%29\" Plug in \"y=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=0\" Solve for x\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the x-intercept is (0,0). Since there can only be one y-intercept, the y-intercept is also (0,0)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let's use this info to graph \"y=%283x%29%2F%28x%5E2-5x%2B6%29\":\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Graph of \"y=%283x%29%2F%28x%5E2-5x%2B6%29%29\" with the horizontal asymptote \"y=0\" (blue line) , the vertical asymptotes \"x=3\" and \"x=2\" (green lines), and the x and y intercept (0,0)
\n" ); document.write( "
\n" ); document.write( "
\n" );