document.write( "Question 138680: The velocity is given as \"V=3t%5E2-39t%2B108\". Find the times when the velocity is positive \n" ); document.write( "
Algebra.Com's Answer #101193 by jim_thompson5910(35256)\"\" \"About 
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\"V=3t%5E2-39t%2B108\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"0=3t%5E2-39t%2B108\" Set the equation equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"3%28t-9%29%28t-4%29=0\" Factor the left side \r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"t-9=0\" or \"t-4=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"t=9\" or \"t=4\" Now solve for t in each case\r
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\n" ); document.write( "\n" ); document.write( "So the critical values are:
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\n" ); document.write( "\n" ); document.write( " \"t=9\" or \"t=4\" \r
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\n" ); document.write( "\n" ); document.write( "\"3t%5E2-39t%2B108%3E0\" Set the expression greater than zero (remember we want a positive velocity)\r
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\n" ); document.write( "\n" ); document.write( "Now set up a number line and plot the critical values on the number line\r
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\n" ); document.write( "\n" ); document.write( "\"number_line%28+600%2C+-10%2C+10%2C9%2C4%29\"\r
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\n" ); document.write( "\n" ); document.write( "So let's pick some test points that are near the critical values and evaluate them.\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is less than \"4\" (notice how it's to the left of the leftmost endpoint):\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"t=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"3t%5E2-39t%2B108%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"3%283%29%5E2-39%283%29%2B108%3E+0\" Plug in \"t=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"18%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.\r
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\n" ); document.write( "\n" ); document.write( " So part our solution in interval notation is ()\r
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\n" ); document.write( "\n" ); document.write( "However, since a negative time is not possible, the interval is really [)\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is in between \"4\" and \"9\":\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"t=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"3t%5E2-39t%2B108%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"3%286%29%5E2-39%286%29%2B108%3E+0\" Plug in \"t=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"-18%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is greater than \"9\" (notice how it's to the right of the rightmost endpoint):\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"t=10\"\r
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\n" ); document.write( "\n" ); document.write( "\"3t%5E2-39t%2B108%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"3%2810%29%5E2-39%2810%29%2B108%3E+0\" Plug in \"t=10\"\r
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\n" ); document.write( "\n" ); document.write( "\"18%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.\r
\n" ); document.write( "\n" ); document.write( " So part our solution in interval notation is ()\r
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\n" ); document.write( "\n" ); document.write( "Summary:\r
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\n" ); document.write( "\n" ); document.write( "So the solution in interval notation is:\r
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\n" ); document.write( "\n" ); document.write( "[) ()\r
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\n" ); document.write( "\n" ); document.write( "So when the time is in between 0 to 4 seconds, or after 9 seconds, then the velocity is positive.
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