document.write( "Question 138664: Find the horizontal and vertical asymptotes of \"y=%28x%5E2-9%29%2F%282x%5E2%2B5x-12%29%29\" \n" ); document.write( "
Algebra.Com's Answer #101186 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"y=%28x%5E2-9%29%2F%282x%5E2%2B5x-12%29%29\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "Looking at the numerator \"x%5E2-9\", we can see that the degree is \"2\" since the highest exponent of the numerator is \"2\". For the denominator \"2x%5E2%2B5x-12\", we can see that the degree is \"2\" since the highest exponent of the denominator is \"2\".\r
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\n" ); document.write( "\n" ); document.write( " Horizontal Asymptote: \r
\n" ); document.write( "\n" ); document.write( "Since the degree of the numerator and the denominator are the same, we can find the horizontal asymptote using this procedure:\r
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\n" ); document.write( "\n" ); document.write( "To find the horizontal asymptote, first we need to find the leading coefficients of the numerator and the denominator.\r
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\n" ); document.write( "\n" ); document.write( "Looking at the numerator \"x%5E2-9\", the leading coefficient is \"1\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the denominator \"2x%5E2%2B5x-12\", the leading coefficient is \"2\"\r
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\n" ); document.write( "\n" ); document.write( "So the horizontal asymptote is the ratio of the leading coefficients. In other words, simply divide \"1\" by \"2\" to get \"%281%29%2F%282%29=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "So the horizontal asymptote is \"y=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( " Vertical Asymptote: \r
\n" ); document.write( "\n" ); document.write( "To find the vertical asymptote, just set the denominator equal to zero and solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B5x-12=0\" Set the denominator equal to zero\r
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\n" ); document.write( "\n" ); document.write( " Now let's use the quadratic formula to solve for x. If you need help with the quadratic formula, check out this solver.\r
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\n" ); document.write( "\n" ); document.write( " After using the quadratic formula, we get the solutions\r
\n" ); document.write( "\n" ); document.write( " \"x=3%2F2\" or \"x=-4\"\r
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\n" ); document.write( "\n" ); document.write( " So this means the vertical asymptotes are \"x=3%2F2\" or \"x=-4\"
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=%28x%5E2-9%29%2F%282x%5E2%2B5x-12%29\", we can visually verify our answers:\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%28x%5E2-9%29%2F%282x%5E2%2B5x-12%29%29\" with the horizontal asymptote \"y=1%2F2\" (blue line) and the vertical asymptotes \"x=3%2F2\" and \"x=-4\" (green lines)
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