document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=138606>Question 138606</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. 696 feet of fencing is used. Find the maximum area of the playground </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101173 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101173\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. 696 feet of fencing is used. Find the maximum area of the playground<BR>\n" );
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document.write( "Let x = length of one side<BR>\n" );
document.write( "Let L = length of the adjacent side:<BR>\n" );
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document.write( "An equation with 3 sides with a length of x, and two with a length of L<BR>\n" );
document.write( "3x + 2L = 696<BR>\n" );
document.write( "2L = 696 - 3x<BR>\n" );
document.write( "L = (348 - 1.5x); divided both sides by 2<BR>\n" );
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document.write( "Area = L*x<BR>\n" );
document.write( "Substitute (348-1.5x) for L<BR>\n" );
document.write( "A = x(348-1.5x)<BR>\n" );
document.write( "A = 348x - 1.5x^2<BR>\n" );
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document.write( "Arrange like a quadratic<BR>\n" );
document.write( "A = -1.5x^2 + 358x<BR>\n" );
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document.write( "Find the axis of symmetry, this is the value of x for max area<BR>\n" );
document.write( "x = -b/(2a); in our equation a = -1.5; b = 348<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-348%29%2F%282%2A-1.5%29 ALIGN=MIDDLE  ALT=\"%28-348%29%2F%282%2A-1.5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-348%29%2F%28-3%29 ALIGN=MIDDLE  ALT=\"%28-348%29%2F%28-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = +116 is dimension of x for max area<BR>\n" );
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document.write( "Find the max area; substitute 116 for x in the equation:<BR>\n" );
document.write( "A = -1.5(116^2) + 348(116)<BR>\n" );
document.write( "A = -1.5(13456) + 40368<BR>\n" );
document.write( "A = -20184 + 40368<BR>\n" );
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document.write( "A = +20,184 sq ft is max area<BR>\n" );
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document.write( "Did I make this understandable, this fine Saturday morning? </SPAN>\n" );
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