document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=138626>Question 138626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of tangents to <BR>\n" );
document.write( " x^2+y^2-6x-2y+9=0<BR>\n" );
document.write( "through the origion. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101170 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101170\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equation of tangents to <BR>\n" );
document.write( "x^2+y^2-6x-2y+9=0<BR>\n" );
document.write( "through the origin.<BR>\n" );
document.write( "-------------------------<BR>\n" );
document.write( "Take the derivative to get:<BR>\n" );
document.write( "2x+2yy'-6-2y'=0<BR>\n" );
document.write( "y'(2y-2) = (6-2x)<BR>\n" );
document.write( "y' = (6-2x)/(2y-2)<BR>\n" );
document.write( "y'(0,0) = 6/-2 = -3<BR>\n" );
document.write( "--------------------------<BR>\n" );
document.write( "Equation of the tangent at (0,0) is y = -3x<BR>\n" );
document.write( "==========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );