document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=138607>Question 138607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> To Stanbon,\r<BR>\n" );
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document.write( "Using the first problem you solved on z-score please check this problem I tried to solve:<BR>\n" );
document.write( "The mean weight of 545 women is 99lbs. and s is 5, Assuming that the wts. of women are normally distributed, how many would you expect to weigh less than 105?\r<BR>\n" );
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document.write( "Z= 105-99/5<BR>\n" );
document.write( "z=1.2<BR>\n" );
document.write( "from table: Z score = .3848 or 38.48% will weigh more than 105 that is 210 women<BR>\n" );
document.write( "computing for women who will weigh less than 105:  <BR>\n" );
document.write( "           100-38.48 = 61.52%<BR>\n" );
document.write( "           545x.6152 = 335 women who will weigh less 105 lbs. \r<BR>\n" );
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document.write( "Thanks again.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101155 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mean weight of 545 women is 99lbs. and s is 5, Assuming that the wts. of women are normally distributed, how many would you expect to weigh less than 105? <BR>\n" );
document.write( "Z= (105-99)/5<BR>\n" );
document.write( "z=1.2<BR>\n" );
document.write( "That is correct.<BR>\n" );
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document.write( "P(0 < x < 105) = P(-19.8 < z < 1.2) = 0.8848 or 88.48%\r<BR>\n" );
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document.write( "from table: Z score = .3848 or 38.48% will weigh more than 105<BR>\n" );
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document.write( "No: 38.48% will weigh more than the MEAN score of 99 lbs.<BR>\n" );
document.write( "You have to include the 50% who weigh less than 99 lbs.<BR>\n" );
document.write( "What that means is you need a z-score for \"0\" lbs.<BR>\n" );
document.write( "z(0) = (0-99)/5 = -19.8<BR>\n" );
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document.write( "Then 88.48% of 545 is 482 ladies who will weigh less than 105 lbs.<BR>\n" );
document.write( "So 545-482 = 63 will weight more than 105 lbs.<BR>\n" );
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document.write( "Recommendation: I think if you draw the normal curve and<BR>\n" );
document.write( "put the problem values on the horizontal axis and shade the<BR>\n" );
document.write( "area under the curve that corresponds to the probability<BR>\n" );
document.write( "you are looking for, you will avoid some errors you might<BR>\n" );
document.write( "otherwise make when you only manipulate the numbers.<BR>\n" );
document.write( "You will be able to see how your answers make sense,or don't.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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