document.write( "Question 138583: The approximate distance above sea level,d, in kilometres, is given by the formula d= (400(log(P/2)-2.5))/30, where P is the barametric pressure in kilopascals(kPa). What is the barometric pressure 12 kilometres above sea level? PLEASE HELP ME :) \n" ); document.write( "
Algebra.Com's Answer #101153 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The approximate distance above sea level,d, in kilometres, is given by the formula d= (400(log(P/2)-2.5))/30, where P is the barametric pressure in kilopascals(kPa). What is the barometric pressure 12 kilometres above sea level?
\n" ); document.write( ":
\n" ); document.write( "Substitute 12 for d in the formula
\n" ); document.write( "\"%28400%28log%28%28P%2F2%29%29-2.5%29%29%2F30\" = 12
\n" ); document.write( ":
\n" ); document.write( "Multiply both sides by 30 to get rid of the denominator
\n" ); document.write( "400(log(p/2)) - 2.5 = 30 * 12
\n" ); document.write( ":
\n" ); document.write( "400(log(p/2)) - 2.5 = 360
\n" ); document.write( ":
\n" ); document.write( "Divide both sides by 400:
\n" ); document.write( "log(p/2) - 2.5 = \"360%2F400\"
\n" ); document.write( "log(p/2) - 2.5 = .9
\n" ); document.write( ":
\n" ); document.write( "Add 2.5 to both sides:
\n" ); document.write( "log(p/2) = .9 + 2.5
\n" ); document.write( "log(p/2) = 3.4
\n" ); document.write( ":
\n" ); document.write( "Find 10^x of both sides
\n" ); document.write( "\"p%2F2\" = 2511.8864
\n" ); document.write( "Multiply both sides by 2
\n" ); document.write( "p = 2511.8864 * 2
\n" ); document.write( ":
\n" ); document.write( "P = 5023.77 kPa
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution on calc; enter:(400(log(5023.77/2)-2.5))/30 = 11.9999 ~ 12 \n" ); document.write( "
\n" );