document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=18160>Question 18160</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves a city heading west and travels at 50 miles per hour. Three hours later, a second train leaves fromt he same place and travels in the same directions at 65 miles per hour.  how long will it take for the second train to overtake the first train? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10114 by </B><A HREF=/tutors/aboutme.mpl?userid=kapilsinghi><B>kapilsinghi(68)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kapilsinghi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10114\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let both trains meet each other x hours after second train starts\r<BR>\n" );
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document.write( "Time taken by train 1 will be = x+3<BR>\n" );
document.write( "distance covered by train 1  = 50(x+3)\r<BR>\n" );
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document.write( "Time taken by train 2 will be = x<BR>\n" );
document.write( "distance covered by train 2  = 65(x)<BR>\n" );
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document.write( "bothe distances will be equal\r<BR>\n" );
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document.write( "so   65x = 50(x+3)<BR>\n" );
document.write( "     65x = 50x+150<BR>\n" );
document.write( "     65x - 50x = 150<BR>\n" );
document.write( "     15x = 150<BR>\n" );
document.write( "      x  = 150/15<BR>\n" );
document.write( "      x  = 10  \r<BR>\n" );
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document.write( "ans 10 Hours\r<BR>\n" );
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