document.write( "Question 138577: I need to slove by completing the square
\n" ); document.write( "m^2-1/2 m=7/2
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Algebra.Com's Answer #101130 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
I don't know how to slove anything. But I will show you how to solve by completing the square.\r
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\n" ); document.write( "\n" ); document.write( "\"m%5E2-%281%2F2%29+m=7%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Step 1 is to put the constant term on the left, but that is already done.\r
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\n" ); document.write( "\n" ); document.write( "Step 2: Divide the coefficient on the 1st degree term by 2, square the result, and then add that result to both sides of the equation. \"%28%28-1%2F2%29%2F2%29%5E2=%28-1%2F4%29%5E2=1%2F16\", so:\r
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\n" ); document.write( "\n" ); document.write( "\"m%5E2-%281%2F2%29m%2B1%2F16=7%2F2%2B1%2F16\"
\n" ); document.write( "\"m%5E2-%281%2F2%29m%2B1%2F16=57%2F16\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3: Factor the perfect square trinomial on the left:
\n" ); document.write( "\"%28m-1%2F4%29%5E2=57%2F16\"\r
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\n" ); document.write( "\n" ); document.write( "Step 4: Take the square root of both sides, remembering to consider both the positive and negative root.\r
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\n" ); document.write( "\n" ); document.write( "\"m-1%2F4=sqrt%2857%2F16%29\" or \"m-1%2F4=-sqrt%2857%2F16%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 5: Add the opposite of the constant on the left to both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"m=1%2F4%2B-sqrt%2857%2F16%29\"\r
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\n" ); document.write( "\n" ); document.write( "And finally simplify the radical:\r
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\n" ); document.write( "\n" ); document.write( "\"m=%281%2B-sqrt%2857%29%29%2F4\"
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