document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=138578>Question 138578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> f(x)=16x^2+40x+25<BR>\n" );
document.write( "What is the y-intercept?<BR>\n" );
document.write( "What is the x-intercept? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #101128 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=101128\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The y-intercept is the point where the curve crosses the y-axis, all of the x-coordinates of points on the y-axis are 0, so just evaluate f(0) (substitute 0 for x in your function and do the arithmetic)  The y-intercept will be the ordered pair (0,b) where b is the result of your evaluation of f(0).\r<BR>\n" );
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document.write( "The x-intercepts are the points where the curve intersects the x-axis.  These are the values of x that make the value of the function be zero.  So just set the function equal to zero and solve the quadratic.  The x-intercepts will be ordered pairs of the form (a,0) where a is a root of the quadratic equation.  Hint: this quadratic is a perfect square so you will only have one intercept. </SPAN>\n" );
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