document.write( "Question 138487: From daughters [age 14] schoolbook with no ISBN.
\n" ); document.write( "x+1 over 3 = -x over 6\r
\n" ); document.write( "\n" ); document.write( "Thanks, you are great. I am learning lots from browsing here
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Algebra.Com's Answer #101114 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"%28%28x%2B1%29%29%2F3\" = \"%28-x%29%2F6\"
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\n" ); document.write( "The easiest way to solve these type of problems, where you have single faction on
\n" ); document.write( "each side of the equal sign, is to cross multiply, resulting in:
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\n" ); document.write( "6(x+1) = 3(-x)
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\n" ); document.write( "Multiply what's inside the brackets
\n" ); document.write( "6x + 6 = -3x
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\n" ); document.write( "Subtract 6 from both sides:
\n" ); document.write( "6x = -3x - 6
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\n" ); document.write( "Add 3x to both sides
\n" ); document.write( "6x + 3x = -6
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\n" ); document.write( "9x = -6
\n" ); document.write( "x = \"%28-6%29%2F9\"; divided both sides by 9
\n" ); document.write( "x = \"-2%2F3\"; reduced the fraction
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\n" ); document.write( "Check solution in original equation:
\n" ); document.write( "\"%28%28x%2B1%29%29%2F3\" = \"%28-x%29%2F6\"
\n" ); document.write( "Substitute -2/3 for x
\n" ); document.write( "\"%28%28%28-2%2F3%29%2B1%29%29%2F3\" = \"%28-%28-2%2F3%29%29%2F6\"
\n" ); document.write( "\"%28%281%2F3%29%29%2F3\" = \"%28%282%2F3%29%29%2F6\"; minus a minus is a plus
\n" ); document.write( "Invert the divisors and mult
\n" ); document.write( "\"%281%2F3%29%2A%281%2F3%29\" = \"%282%2F3%29%2A%281%2F6%29\"
\n" ); document.write( "\"1%2F9\" = \"2%2F18\"; equality reigns, confirms our solution
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