document.write( "Question 138482: The perimeter of a rectangle is 208 inches. The length exceeds the width by 32 inches. Find the length and the width.
\n" ); document.write( "The length is ?
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\n" ); document.write( "\n" ); document.write( "The width is ?
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\n" ); document.write( "\n" ); document.write( "Help me please..Thank you so much in advance.
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Algebra.Com's Answer #101106 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The perimeter of a rectangle is 208 inches. The length exceeds the width by 32 inches. Find the length and the width.
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\n" ); document.write( "Let the width be \"x\" in. ; then the length will be \"x+32\" in.
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\n" ); document.write( "Formula:
\n" ); document.write( "Perimeter = 2(length + width)
\n" ); document.write( "208 = 2(x+32 + x)
\n" ); document.write( "104 = 2x+32
\n" ); document.write( "2x = 72
\n" ); document.write( "x = 36 in. (this is the width)
\n" ); document.write( "x+32 = 68 in. (this is the length)
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\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "The length is ?
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\n" ); document.write( "The width is ?
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